rune.c (4243B)
1 /* MIT/X Consortium Copyright (c) 2012 Connor Lane Smith <cls@lubutu.com> 2 * 3 * Permission is hereby granted, free of charge, to any person obtaining a 4 * copy of this software and associated documentation files (the "Software"), 5 * to deal in the Software without restriction, including without limitation 6 * the rights to use, copy, modify, merge, publish, distribute, sublicense, 7 * and/or sell copies of the Software, and to permit persons to whom the 8 * Software is furnished to do so, subject to the following conditions: 9 * 10 * The above copyright notice and this permission notice shall be included in 11 * all copies or substantial portions of the Software. 12 * 13 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR 14 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, 15 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL 16 * THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER 17 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING 18 * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER 19 * DEALINGS IN THE SOFTWARE. 20 */ 21 #include "../utf.h" 22 23 #define MIN(x,y) ((x) < (y) ? (x) : (y)) 24 25 #define UTFSEQ(x) ((((x) & 0x80) == 0x00) ? 1 /* 0xxxxxxx */ \ 26 : (((x) & 0xC0) == 0x80) ? 0 /* 10xxxxxx */ \ 27 : (((x) & 0xE0) == 0xC0) ? 2 /* 110xxxxx */ \ 28 : (((x) & 0xF0) == 0xE0) ? 3 /* 1110xxxx */ \ 29 : (((x) & 0xF8) == 0xF0) ? 4 /* 11110xxx */ \ 30 : (((x) & 0xFC) == 0xF8) ? 5 /* 111110xx */ \ 31 : (((x) & 0xFE) == 0xFC) ? 6 /* 1111110x */ \ 32 : 0 ) 33 34 #define BADRUNE(x) ((x) < 0 || (x) > Runemax \ 35 || ((x) & 0xFFFE) == 0xFFFE \ 36 || ((x) >= 0xD800 && (x) <= 0xDFFF) \ 37 || ((x) >= 0xFDD0 && (x) <= 0xFDEF)) 38 39 int 40 runetochar(char *s, const Rune *p) 41 { 42 Rune r = *p; 43 44 switch(runelen(r)) { 45 case 1: /* 0aaaaaaa */ 46 s[0] = r; 47 return 1; 48 case 2: /* 00000aaa aabbbbbb */ 49 s[0] = 0xC0 | ((r & 0x0007C0) >> 6); /* 110aaaaa */ 50 s[1] = 0x80 | (r & 0x00003F); /* 10bbbbbb */ 51 return 2; 52 case 3: /* aaaabbbb bbcccccc */ 53 s[0] = 0xE0 | ((r & 0x00F000) >> 12); /* 1110aaaa */ 54 s[1] = 0x80 | ((r & 0x000FC0) >> 6); /* 10bbbbbb */ 55 s[2] = 0x80 | (r & 0x00003F); /* 10cccccc */ 56 return 3; 57 case 4: /* 000aaabb bbbbcccc ccdddddd */ 58 s[0] = 0xF0 | ((r & 0x1C0000) >> 18); /* 11110aaa */ 59 s[1] = 0x80 | ((r & 0x03F000) >> 12); /* 10bbbbbb */ 60 s[2] = 0x80 | ((r & 0x000FC0) >> 6); /* 10cccccc */ 61 s[3] = 0x80 | (r & 0x00003F); /* 10dddddd */ 62 return 4; 63 default: 64 return 0; /* error */ 65 } 66 } 67 68 int 69 chartorune(Rune *p, const char *s) 70 { 71 return charntorune(p, s, UTFmax); 72 } 73 74 int 75 charntorune(Rune *p, const char *s, size_t len) 76 { 77 unsigned int i, n; 78 Rune r; 79 80 if(len == 0) /* can't even look at s[0] */ 81 return 0; 82 83 switch((n = UTFSEQ(s[0]))) { 84 case 1: r = s[0]; break; /* 0xxxxxxx */ 85 case 2: r = s[0] & 0x1F; break; /* 110xxxxx */ 86 case 3: r = s[0] & 0x0F; break; /* 1110xxxx */ 87 case 4: r = s[0] & 0x07; break; /* 11110xxx */ 88 case 5: r = s[0] & 0x03; break; /* 111110xx */ 89 case 6: r = s[0] & 0x01; break; /* 1111110x */ 90 default: /* invalid sequence */ 91 *p = Runeerror; 92 return 1; 93 } 94 /* add values from continuation bytes */ 95 for(i = 1; i < MIN(n, len); i++) 96 if((s[i] & 0xC0) == 0x80) { 97 /* add bits from continuation byte to rune value 98 * cannot overflow: 6 byte sequences contain 31 bits */ 99 r = (r << 6) | (s[i] & 0x3F); /* 10xxxxxx */ 100 } 101 else { /* expected continuation */ 102 *p = Runeerror; 103 return i; 104 } 105 106 if(i < n) /* must have reached len limit */ 107 return 0; 108 109 /* reject invalid or overlong sequences */ 110 if(BADRUNE(r) || runelen(r) < (int)n) 111 r = Runeerror; 112 113 *p = r; 114 return n; 115 } 116 117 int 118 runelen(Rune r) 119 { 120 if(BADRUNE(r)) 121 return 0; /* error */ 122 else if(r <= 0x7F) 123 return 1; 124 else if(r <= 0x07FF) 125 return 2; 126 else if(r <= 0xFFFF) 127 return 3; 128 else 129 return 4; 130 } 131 132 size_t 133 runenlen(const Rune *p, size_t len) 134 { 135 size_t i, n = 0; 136 137 for(i = 0; i < len; i++) 138 n += runelen(p[i]); 139 return n; 140 } 141 142 int 143 fullrune(const char *s, size_t len) 144 { 145 Rune r; 146 147 return charntorune(&r, s, len) > 0; 148 }